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#!/usr/bin/env python

""" Python implementation of ASCII85/ASCIIHex decoder (Adobe version).

This code is in the public domain.

"""

import re
import struct


# ascii85decode(data)
def ascii85decode(data):
    """
    In ASCII85 encoding, every four bytes are encoded with five ASCII
    letters, using 85 different types of characters (as 256**4 < 85**5).
    When the length of the original bytes is not a multiple of 4, a special
    rule is used for round up.

    The Adobe's ASCII85 implementation is slightly different from
    its original in handling the last characters.

    The sample string is taken from:
      http://en.wikipedia.org/w/index.php?title=Ascii85

    >>> ascii85decode(b'9jqo^BlbD-BleB1DJ+*+F(f,q')
    b'Man is distinguished'
    >>> ascii85decode(b'E,9)oF*2M7/c~>')
    b'pleasure.'
    """
    n = b = 0
    out = b''
    for c in data:
        if 33 <= c and c <= 117: # b'!' <= c and c <= b'u'
            n += 1
            b = b*85+(c-33)
            if n == 5:
                out += struct.pack('>L', b)
                n = b = 0
        elif c == 122: # b'z'
            assert n == 0
            out += b'\0\0\0\0'
        elif c == 126: # b'~'
            if n:
                for _ in range(5-n):
                    b = b*85+84
                out += struct.pack('>L', b)[:n-1]
            break
    return out

# asciihexdecode(data)
hex_re = re.compile(r'([a-f\d]{2})', re.IGNORECASE)
trail_re = re.compile(r'^(?:[a-f\d]{2}|\s)*([a-f\d])[\s>]*$', re.IGNORECASE)


def asciihexdecode(data):
    """
    ASCIIHexDecode filter: PDFReference v1.4 section 3.3.1
    For each pair of ASCII hexadecimal digits (0-9 and A-F or a-f), the
    ASCIIHexDecode filter produces one byte of binary data. All white-space
    characters are ignored. A right angle bracket character (>) indicates
    EOD. Any other characters will cause an error. If the filter encounters
    the EOD marker after reading an odd number of hexadecimal digits, it
    will behave as if a 0 followed the last digit.

    >>> asciihexdecode(b'61 62 2e6364   65')
    b'ab.cde'
    >>> asciihexdecode(b'61 62 2e6364   657>')
    b'ab.cdep'
    >>> asciihexdecode(b'7>')
    b'p'
    """
    data = data.decode('latin1')
    out = [ int(hx,16) for hx in  hex_re.findall(data) ]
    m = trail_re.search(data)
    if m:
        out.append(int(m.group(1),16) << 4)
    return bytes(out)


if __name__ == '__main__':
    import doctest
    print('pdfminer.ascii85', doctest.testmod())